x=2x^2/800

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Solution for x=2x^2/800 equation:



x=2x^2/800
We move all terms to the left:
x-(2x^2/800)=0
We get rid of parentheses
-2x^2/800+x=0
We multiply all the terms by the denominator
-2x^2+x*800=0
Wy multiply elements
-2x^2+800x=0
a = -2; b = 800; c = 0;
Δ = b2-4ac
Δ = 8002-4·(-2)·0
Δ = 640000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{640000}=800$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(800)-800}{2*-2}=\frac{-1600}{-4} =+400 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(800)+800}{2*-2}=\frac{0}{-4} =0 $

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